Solve for x -2

$- 2 \leq \frac{5 - x}{3} \leq 2$

Multiply each term in the inequality by $3$ .

$- 2 \cdot 3 \leq \frac{5 - x}{3} \cdot 3 \leq 2 \cdot 3$

Multiply $- 2$ by $3$ .

$- 6 \leq \frac{5 - x}{3} \cdot 3 \leq 2 \cdot 3$

Cancel the common factor of $3$ .

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Cancel the common factor.

$- 6 \leq \frac{5 - x}{3} \cdot 3 \leq 2 \cdot 3$

Rewrite the expression.

$- 6 \leq 5 - x \leq 2 \cdot 3$

Multiply $2$ by $3$ .

$- 6 \leq 5 - x \leq 6$

Move all terms not containing $x$ from the center section of the inequality.

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Subtract $5$ from each section of the inequality because it does not contain the variable we are trying to solve for.

$- 6 - 5 \leq - x \leq 6 - 5$

Subtract $5$ from $- 6$ .

$- 11 \leq - x \leq 6 - 5$

Subtract $5$ from $6$ .

$- 11 \leq - x \leq 1$

Multiply each term in the inequality by $- 1$ .

$(- 11) \cdot - 1 \geq (- x) \cdot - 1 \geq 1 \cdot - 1$

Multiply $- 11$ by $- 1$ .

$11 \geq (- x) \cdot - 1 \geq 1 \cdot - 1$

Multiply $(- x) \cdot - 1$ .

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Multiply $- 1$ by $- 1$ .

$11 \geq 1 x \geq 1 \cdot - 1$

Multiply $x$ by $1$ .

$11 \geq x \geq 1 \cdot - 1$

Multiply $- 1$ by $1$ .

$11 \geq x \geq - 1$

Rewrite the interval so that the left value is less than the right value. This is the correct way to write an interval solution.

$- 1 \leq x \leq 11$

Solve for x -2<=(5-x)/3<=2