Solve by Factoring 3x^2-5x=0

$3 x^{2} - 5 x = 0$

Factor $x$ out of $3 x^{2} - 5 x$ .

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Factor $x$ out of $3 x^{2}$ .

$x (3 x) - 5 x = 0$

Factor $x$ out of $- 5 x$ .

$x (3 x) + x \cdot - 5 = 0$

Factor $x$ out of $x (3 x) + x \cdot - 5$ .

$x (3 x - 5) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$3 x - 5 = 0$

Set the first factor equal to $0$ .

$x = 0$

Set the next factor equal to $0$ and solve.

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Set the next factor equal to $0$ .

$3 x - 5 = 0$

Add $5$ to both sides of the equation.

$3 x = 5$

Divide each term by $3$ and simplify.

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Divide each term in $3 x = 5$ by $3$ .

$\frac{3 x}{3} = \frac{5}{3}$

Cancel the common factor of $3$ .

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Cancel the common factor.

$\frac{3 x}{3} = \frac{5}{3}$

Divide $x$ by $1$ .

$x = \frac{5}{3}$

The final solution is all the values that make $x (3 x - 5) = 0$ true.

$x = 0, \frac{5}{3}$

Solve by Factoring 3x^2-5x=0