Find Three Ordered Pair Solutions 4y-x=8

$4 y - x = 8$

Solve the equation for $y$ .

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Add $x$ to both sides of the equation.

$4 y = 8 + x$

Divide each term by $4$ and simplify.

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Divide each term in $4 y = 8 + x$ by $4$ .

$\frac{4 y}{4} = \frac{8}{4} + \frac{x}{4}$

Cancel the common factor of $4$ .

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Cancel the common factor.

$\frac{4 y}{4} = \frac{8}{4} + \frac{x}{4}$

Divide $y$ by $1$ .

$y = \frac{8}{4} + \frac{x}{4}$

Divide $8$ by $4$ .

$y = 2 + \frac{x}{4}$

Choose any value for $x$ that is in the domain to plug into the equation.

Choose $0$ to substitute in for $x$ to find the ordered pair.

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Remove parentheses.

$y = 2 + \frac{0}{4}$

Simplify $2 + \frac{0}{4}$ .

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Divide $0$ by $4$ .

$y = 2 + 0$

Add $2$ and $0$ .

$y = 2$

Use the $x$ and $y$ values to form the ordered pair.

$(0, 2)$

Choose $1$ to substitute in for $x$ to find the ordered pair.

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Remove parentheses.

$y = 2 + \frac{1}{4}$

Simplify $2 + \frac{1}{4}$ .

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To write $2$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$y = 2 \cdot \frac{4}{4} + \frac{1}{4}$

Combine $2$ and $\frac{4}{4}$ .

$y = \frac{2 \cdot 4}{4} + \frac{1}{4}$

Combine the numerators over the common denominator.

$y = \frac{2 \cdot 4 + 1}{4}$

Simplify the numerator.

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Multiply $2$ by $4$ .

$y = \frac{8 + 1}{4}$

Add $8$ and $1$ .

$y = \frac{9}{4}$

Use the $x$ and $y$ values to form the ordered pair.

$(1, \frac{9}{4})$

Choose $2$ to substitute in for $x$ to find the ordered pair.

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Remove parentheses.

$y = 2 + \frac{2}{4}$

Simplify $2 + \frac{2}{4}$ .

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Cancel the common factor of $2$ and $4$ .

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Factor $2$ out of $2$ .

$y = 2 + \frac{2 (1)}{4}$

Cancel the common factors.

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Factor $2$ out of $4$ .

$y = 2 + \frac{2 \cdot 1}{2 \cdot 2}$

Cancel the common factor.

$y = 2 + \frac{2 \cdot 1}{2 \cdot 2}$

Rewrite the expression.

$y = 2 + \frac{1}{2}$

To write $2$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$y = 2 \cdot \frac{2}{2} + \frac{1}{2}$

Combine $2$ and $\frac{2}{2}$ .

$y = \frac{2 \cdot 2}{2} + \frac{1}{2}$

Combine the numerators over the common denominator.

$y = \frac{2 \cdot 2 + 1}{2}$

Simplify the numerator.

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Multiply $2$ by $2$ .

$y = \frac{4 + 1}{2}$

Add $4$ and $1$ .

$y = \frac{5}{2}$

Use the $x$ and $y$ values to form the ordered pair.

$(2, \frac{5}{2})$

These are three possible solutions to the equation.

$(0, 2), (1, \frac{9}{4}), (2, \frac{5}{2})$

Find Three Ordered Pair Solutions 4y-x=8