Find the Perpendicular Line y=3(x-7) , (-7,0)

$y = 3 (x - 7)$ , $(- 7, 0)$

Find the slope when $y = 3 (x - 7)$ .

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Rewrite in slope-intercept form.

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The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Simplify $3 (x - 7)$ .

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Apply the distributive property.

$y = 3 x + 3 \cdot - 7$

Multiply $3$ by $- 7$ .

$y = 3 x - 21$

Using the slope-intercept form, the slope is $3$ .

$m = 3$

The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{3}$

Find the equation of the perpendicular line using the point–slope formula.

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Use the slope $- \frac{1}{3}$ and a given point $(- 7, 0)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (0) = (- \frac{1}{3}) (x - (- 7))$

Simplify the equation and keep it in point-slope form.

$y + 0 = - \frac{1}{3} \cdot (x + 7)$

Write in $y = m x + b$ form.

$y = - \frac{1}{3} x - \frac{7}{3}$

Find the Perpendicular Line y=3(x-7) , (-7,0)