Divide (9a^3-3a^2-3a+9)/(3a+2)

Math
Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of .
++
Divide the highest order term in the dividend by the highest order term in divisor .
++
Multiply the new quotient term by the divisor.
++
++
The expression needs to be subtracted from the dividend, so change all the signs in
++
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
++
Pull the next terms from the original dividend down into the current dividend.
++
Divide the highest order term in the dividend by the highest order term in divisor .
++
Multiply the new quotient term by the divisor.
++
The expression needs to be subtracted from the dividend, so change all the signs in
++
++
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
++
++
+
Pull the next terms from the original dividend down into the current dividend.
++
++
++
Divide the highest order term in the dividend by the highest order term in divisor .
+
++
++
++
Multiply the new quotient term by the divisor.
+
++
++
++
++
The expression needs to be subtracted from the dividend, so change all the signs in
+
++
++
++
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
+
++
++
++
+
The final answer is the quotient plus the remainder over the divisor.
Divide (9a^3-3a^2-3a+9)/(3a+2)
Scroll to top